-36w^2=-7

Solution for -36w^2=-7 equation:

-36w^2=-7

We move all terms to the left:

-36w^2-(-7)=0

We add all the numbers together, and all the variables

-36w^2+7=0

a = -36; b = 0; c = +7;
Δ = b2-4ac
Δ = 02-4·(-36)·7
Δ = 1008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1008}=\sqrt{144*7}=\sqrt{144}*\sqrt{7}=12\sqrt{7}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{7}}{2*-36}=\frac{0-12\sqrt{7}}{-72}
=-\frac{12\sqrt{7}}{-72}
=-\frac{\sqrt{7}}{-6}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{7}}{2*-36}=\frac{0+12\sqrt{7}}{-72}
=\frac{12\sqrt{7}}{-72}
=\frac{\sqrt{7}}{-6}
$